the angle that the vector of A=2ivector+3jvector makes with y axis is find it
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Answered by
0
Answer:
A
=2
i
^
+3
j
^
A
.
j
^
=
13
cosθ
3=
13
cosθ
θ=cos
−1
(
13
3
)
Using formula, tan(cos
−1
x)=
x
1−x
2
we will get:
θ=tan
−1
13
3
1−
13
9
θ=tan
−1
(
3
2
)
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Explanation:
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