Question

the angle that vector A^=2i^+3j^makes with y-axis is

Answer 1

,so, ur answer is ,

See, A cap is given= 2i+3j.....

Now, assume y axis asB^ = j cap,

Then, by dot product rule,
A^.B^=|A|.|B|cos theta,
Now,

We will multipy i with I and j with j
So ,, in B vector there is no i^ so,
Dot product will be, as 3j.j=3
Now, magnitude of AB= ✓13

So , there will be 3/✓13