Math, asked by gowthamreddy096, 6 months ago

The angle through which the axes are to be rotated so as to remove the Xy term in the
equation x² + 4xy + y2 =0 is pi/4
radians then the value of k is

Answers

Answered by nisha02345
2

Answer:

Let axes be rotated through an angle ϕ, then old co-ordinates are

x=x

1

cosϕ−y

1

sinϕ

y=x

1

sinϕ+y

1

cosϕ

∴(x

1

cosϕ−y

1

sinϕ)

2

+2

3

(x

1

cosϕ−y

1

sinϕ)(x

1

sinϕ+y

1

cosϕ)−(x

1

sinϕ+y

1

cosϕ)

2

=2a

2

coefficient of x

1

y

1

is

−2cosϕsinϕ+2

3

(cos

2

ϕ−sin

2

ϕ)−2cosϕsinϕ=0

2

3

(cos2ϕ)=2sin2ϕ

tan2ϕ=

3

⇒2ϕ=

3

π

ϕ=

6

π

∴ angle through which it is to be rotated is

6

π

Answered by Anonymous
2

Answer:

Answer:

Let axes be rotated through an angle ϕ, then old co-ordinates are

x=x

1

cosϕ−y

1

sinϕ

y=x

1

sinϕ+y

1

cosϕ

∴(x

1

cosϕ−y

1

sinϕ)

2

+2

3

(x

1

cosϕ−y

1

sinϕ)(x

1

sinϕ+y

1

cosϕ)−(x

1

sinϕ+y

1

cosϕ)

2

=2a

2

coefficient of x

1

y

1

is

−2cosϕsinϕ+2

3

(cos

2

ϕ−sin

2

ϕ)−2cosϕsinϕ=0

2

3

(cos2ϕ)=2sin2ϕ

tan2ϕ=

3

⇒2ϕ=

3

π

ϕ=

6

π

∴ angle through which it is to be rotated is

6

π

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