Physics, asked by Anagh7678, 19 days ago

The angle turned through by the fly wheel in a time interval t Is given by θ = at + bt^2 + ct^3 where a,b,c are constant where a,b,c are constant. The angular velocity a t = 2s is

Answers

Answered by sathvik7678
1

Given :-

  • The angle turned through by the fly wheel in a time interval t Is given by θ = at + bt² + ct³ where a,b,c are constant where a,b,c are constant. The angular velocity a t = 2s is

Solution :-

  • Here, angular displacement is given to us. We need to find angular velocity at t = 2s.
  • We know that, angular velocity and angular displacement are related as :-

      ω = \sf\frac{d\theta  }{dt}

       Where :-

      → ω is angular velocity

      → θ is angular displacement

  • In the question, it is given that, θ = at + bt² + ct³. So,

         ω = \sf\frac{d}{dt}(at + bt^{2} + ct^{3})

     ⇒ ω = a + 2bt + 3ct²    ------------------- (1)

  • As they asked angular velocity at t = 2s, let us substitute t = 2s in equation (1)

     ⇒ ω = a + 2b(2) + 3c(2)²

     ⇒ ω = a + 4b + 12c

The angular velocity of the fly wheel at t = 2s is a + 4b + 12c

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Thank you, please mark as brainliest!

Sathvik :)

Answered by basanirayapareddy
1

Answer is a + 4b + 12c

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