Question

the angleof triangle are (x+10),(2x-30) and x find the value of x
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Answer 1

Question:-

the angleof triangle are (x+10),(2x-30) and x.find the value of x.

Answer:-

• The angles of triangle are 60°,70° and 50°.

To find:-

• All angles of triangle

Solution:-

The angles of triangle are:-

• x+ 10
• 2x - 30
• x

Sum of all angles of triangle is 180°

$\large{: \implies \: (x + 10) + (2x - 30) + x = 180}$

$\large{: \implies \: 4x - 20 = 180}$

$\large{: \implies \: 4x = 180 + 20}$

$\large{: \implies \: 4x = 200}$

$\large{: \implies \: x \: = \frac{200}{4} }$

$\large{: \implies \: x = 50}$

• The value of x is 50°

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ANGLES ARE:-

• x + 10 = 50 + 10 = 60°
• 2x - 30 =2× 50 - 30 = 100 - 30 = 70°
• x = 50°

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The angles of triangle are 60°,70° and 50°.