Question

The angles A, B, C and D of a trapezium ABCD are in the ratio 3: 4:5:6.
i.e. AngleA : angleB : angleC: angleD = 3: 4: 5: 6. Find all the angles of the trapezium. Also,
name the two sides of this trapezium which are parallel to each other. Give reason for
your answer.
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Answer 1

Answer:

The sum of all the angles of a trapezium is 360 degrees

so let angle A be 3x , angle B be 4x , angle C be 5x and angle D be 6x

We know that :-

angle A + angle B + angle C + angle D = 360 °

3x + 4x + 5x + 6x = 360°

18x = 360°

x = 360°÷ 18 = 20

x = 20

so angle A = 3 × 20= 60

angle A = 60°

angle B = 4 × 20 = 80

angle B = 80°

angle C = 5 × 20 = 100 °

angle D = 6 × 20 = 120°

The two sides which are parallel = AB and CD

I THINK THAT THIS IS THE WHOLE AND CORRECT ANSWER AND PLEASE MARK ME AS BRAINIEST