the angles A,B,C and. D of quadrilateral ABCD are in ratio 1 :3:7:9.
i) find the measure of each angle
ii)is ABCD a trapezium? why
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Let angles be 1x,3x,7x,9x
Now sum of all angles of a quadrilateral is 360
So, 1x+3x+7x+9x=360
20x=360
X=360/20
X=18
Angles will be 1×18=18
3×18=54
7×18=126
9×18=162
Yes it is a trapazium because it doesn't have any angle of 90 and all angles are different.
Now sum of all angles of a quadrilateral is 360
So, 1x+3x+7x+9x=360
20x=360
X=360/20
X=18
Angles will be 1×18=18
3×18=54
7×18=126
9×18=162
Yes it is a trapazium because it doesn't have any angle of 90 and all angles are different.
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1:3:7:9 =x+3x+7x+9x= 20x
20x=360°
x=18°
3x=54°
7x=126°
9x=162°
sum of 18°+162°=180°
sum of 54+126= 180
sum adjecent angle of trapezium equal to 180°
20x=360°
x=18°
3x=54°
7x=126°
9x=162°
sum of 18°+162°=180°
sum of 54+126= 180
sum adjecent angle of trapezium equal to 180°
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