Question

The angles A, B, C, D of a quardrilateral ABCD taken in order are in the ratio 3:7:6:4, then ABCD is a:

Answer 1

Step-by-step explanation:

let the angles A, B, C, D be 3x , 7x, 6x, and, 4x respectively

so according to question :-

3x + 7x + 6x +4x = 360

20x = 360

x = 360/20= 18

so a = 3*18 = 54

b = 7*18= 126

c = 6*18= 108

d = 4*18 = 72

so ABCD is a trapezium

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Answer 2

Step-by-step explanation:

Given, angle A =3x

angle B =7x

angle C =6x

angle D =4x

As we know that,

the sum of all angles of quad. = 360°

therefore, angle( A+B +C + D) = 360°

3x+7x+6x+4x =360°

20x = 360°

x. = 360°/ 20

x = 18°

hence, angle A= 3x = 3×18 = 54°

angle B = 7x = 7×18 = 126°

angle C = 6x = 6×18 = 108°

angle D = 4x = 4×18 = 72°