Question

The angles are adjacent and form an angle of 140°. The smaller is 28 less than the larger​

Answer 1

$\huge\fcolorbox{yellow}{aqua} {Answer}$

The two adjacent angles add up to 140140 .

The two adjacent angles add up to 140140 .Therefore the sum of the two should give 140.

The two adjacent angles add up to 140140 .Therefore the sum of the two should give 140.Let the larger be x then the smaller is x−28

The two adjacent angles add up to 140140 .Therefore the sum of the two should give 140.Let the larger be x then the smaller is x−28x+x−28=140

The two adjacent angles add up to 140140 .Therefore the sum of the two should give 140.Let the larger be x then the smaller is x−28x+x−28=1402x−28=140

The two adjacent angles add up to 140140 .Therefore the sum of the two should give 140.Let the larger be x then the smaller is x−28x+x−28=1402x−28=1402x=140+28=168

The two adjacent angles add up to 140140 .Therefore the sum of the two should give 140.Let the larger be x then the smaller is x−28x+x−28=1402x−28=1402x=140+28=1682x=168 (divide both sides by two)

The two adjacent angles add up to 140140 .Therefore the sum of the two should give 140.Let the larger be x then the smaller is x−28x+x−28=1402x−28=1402x=140+28=1682x=168 (divide both sides by two)x=84 (the larger angle)

The two adjacent angles add up to 140140 .Therefore the sum of the two should give 140.Let the larger be x then the smaller is x−28x+x−28=1402x−28=1402x=140+28=1682x=168 (divide both sides by two)x=84 (the larger angle)84−28=56 (the smaller angle)

The two adjacent angles add up to 140140 .Therefore the sum of the two should give 140.Let the larger be x then the smaller is x−28x+x−28=1402x−28=1402x=140+28=1682x=168 (divide both sides by two)x=84 (the larger angle)84−28=56 (the smaller angle)The two angles are 84 and 56.

Answer 2

Answer:

so guys this ur answer. 56,84