Question

the angles are supplementary and the larger is 58 degree more than the smaller. ​

Answer 1

Answer:

Lets take the smaller angle as x.

and the larger angle as y.

Therefore,

it is given that x+58°=y

y+x=180°

Instead of y we can write x+58

Therefore,

x+58°+x=180°

2x+58=180

2x=180-58

x=122/2

x=61°

Therefore,

If x=61°

then y is = x+58

=61+58

= 119°

Answer 2

Question: Two angles are supplementary, and the larger angle is 58 degrees more than the smaller angle. Find the value of both the angles.

Let the greater angle be 'x'

Let the smaller angle be 'y'

ATQ,

The two angles are supplementary.

⇒ x + y = 180°

↑ Let the above equation be Eq(1)

And, The Larger ∠x is 58°'s greater than ∠y.

⇒ x = y + 58°

⇒ x - y = 58°

↑ Let the above equation be Eq(2)

Adding Eq(1) and Eq(2) we get,

$\sf x + y = 180^\circ\\x - y = 58^\circ\\------\\2x = 238$

$\sf x = \dfrac{238}{2}$

x = 119°

Now, Substitute the value of 'x' in Eq(1).

x + y = 180°

119° + y = 180°

y = 180° - 119°

y = 61°

Answers:

x $\longrightarrow$ 119°

y $\longrightarrow$ 61°