the angles between lines y+5=0, root of 3x-y-7=0 is.
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Answer:
tan^(-1) √3 = π/3
Step-by-step explanation:
slope of y + 5 = 0 can be determined using y = mx + c where m is the slope.
slope of this line is 0.
Similarly,
slope of √3x - y - 7 = 0 is √3
Using: if angle between between two lines is A and m & n are slopes of those lines then:
tanA = | (m - n)/(1 + mn) |
Therefore, let B be the angle b/w them
tanB = |(0 - (√3))/(1 + 0)| = √3
tanB = tan(π/3)
B = π/3
Moreover, notice that y + 5 is a horizontal side. As our point of reference for any slope is x-axis(same horizon), we can directly say 'angle between them is the angle between √3x - y - 7 = 0 and x-axis e.i. inverese tan of slope'.
angle = tan^(-1) √3
we say this arctan3 or tan inverse √3, that is π/3
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