Math, asked by nirmaladevihm, 1 month ago

the angles between lines y+5=0, root of 3x-y-7=0 is.​

Answers

Answered by abhi569
1

Answer:

tan^(-1) √3 = π/3

Step-by-step explanation:

slope of y + 5 = 0 can be determined using y = mx + c where m is the slope.

slope of this line is 0.

Similarly,

slope of √3x - y - 7 = 0 is √3

Using: if angle between between two lines is A and m & n are slopes of those lines then:

tanA = | (m - n)/(1 + mn) |

Therefore, let B be the angle b/w them

tanB = |(0 - (√3))/(1 + 0)| = √3

tanB = tan(π/3)

B = π/3

Moreover, notice that y + 5 is a horizontal side. As our point of reference for any slope is x-axis(same horizon), we can directly say 'angle between them is the angle between √3x - y - 7 = 0 and x-axis e.i. inverese tan of slope'.

angle = tan^(-1) √3

we say this arctan3 or tan inverse √3, that is π/3

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