Question

The angles f the triangle are in the ratio 3:6:1. Find the measure of largest angle
in the triangle.​

Answer 1

Answer:

3x+6x+X=180

10x=180

X=180/10

X=18

first angle=3x18=54

second angle=6x18=108

third angle=18

largest angle is 108

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Answer 2

Let the angles be 3x,6x,x

perimeter of triangle = sum of all sides

180. = 3x + 6x + x

180 = 10x

x = 180/10

x = 18

So, the angles are 3x = 3(18)

= 54

6x = 6(18)

= 108

x = 18

therefore, the largest angle of the triangle is 108.

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