the angles in a quadrilateral x+50,x-50,X+70,2x+10 find the measures of each angle
jsaidisha:
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Hi friend ,
Here is your answer
Lets take the quadrilateral ABCD .
In this let's take ,
angle A = x + 50
angle B = x - 50
angle C = x + 70
angle D = 2x + 10
We already know that sum of all angles in a quadrilateral is 360° .
So ,
angle A + angle B + angle C + angle D = 360°
x + 50 + x - 50 + x + 70 + 2x + 10 = 360°
5x + 80 = 360°
5x = 360 - 80 = 280
x = 280/5 = 56
angle A = 56 +50 = 106
angle B = 56 - 50 = 6
angle C = 56 + 70 = 126
angle D = 2(56) + 10 = 122
Hope it helps
Pls mark as brainliest
Here is your answer
Lets take the quadrilateral ABCD .
In this let's take ,
angle A = x + 50
angle B = x - 50
angle C = x + 70
angle D = 2x + 10
We already know that sum of all angles in a quadrilateral is 360° .
So ,
angle A + angle B + angle C + angle D = 360°
x + 50 + x - 50 + x + 70 + 2x + 10 = 360°
5x + 80 = 360°
5x = 360 - 80 = 280
x = 280/5 = 56
angle A = 56 +50 = 106
angle B = 56 - 50 = 6
angle C = 56 + 70 = 126
angle D = 2(56) + 10 = 122
Hope it helps
Pls mark as brainliest
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