The angles of a a quadrilateral are in A.P. The greatest angle is double the least. Find all the four angles.
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Since all angles are in Ap
Let the four angles be a,a+x,a+2x,a+3x
According to the question,
4×a=a+3x
3a=3x
a=x
Therefore the four angles become
a,2a,3a,4a
A/q,10a=360
a=36
2a=72
3a=108
4a=144
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