Question

.
The angles of a
a triangle are 3x ( 2x+20) and ( 5x-40). Find the angles.

CAN ANYONE DO THIS SUM....ITS VERY URJENT...​

Answer 1

Concept used

Angle sum property (triangle) : This property is only applicable for triangles. It might be any triangle, equilateral, isosceles or scalene. This property is also applicable for all the types of angle based triangles. All the figures that has three sides and angles should have the sum of their angles as 180°. This is the rule of this concept. If this rule is not accepted by any triangle, then that figure cannot be classified as a triangle. This same rule will be used in this question.

${\sf \dashrightarrow {Angle \: sum \: property}_{(Triangle)} = {180}^{\circ}}$

$\sf \dashrightarrow 3x + (2x + 20) + (5x - 40) = {180}^{\circ}$

$\sf \dashrightarrow 10x + 20 - 40 = {180}^{\circ}$

$\sf \dashrightarrow 10x - 20 = {180}^{\circ}$

$\sf \dashrightarrow 10x = 180 + 20$

$\sf \dashrightarrow 10x = 200$

$\sf \dashrightarrow x = \dfrac{200}{10}$

$\sf \dashrightarrow x = 20$

Now, we can find all the values of those angles of the triangle.

Measurement of first angle :

$\sf \dashrightarrow 3x = 3(20)$

$\sf \dashrightarrow {60}^{\circ}$

Measurement of second angle :

$\sf \dashrightarrow 2x + 20 = 2(20) + 20$

$\sf \dashrightarrow 40 + 20$

$\sf \dashrightarrow {60}^{\circ}$

Measurement of third angle :

$\sf \dashrightarrow 5x - 40 = 5(20) - 40$

$\sf \dashrightarrow 100 - 40$

$\sf \dashrightarrow {60}^{\circ}$

Hence, all the angles of the triangle measures 60°.