The angles of a Δ are (x − 40)°, (x − 20)° and ( x 10)°. Find the 2
1 −
value of x , also find all the angles of the Δ .
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Sum of angles of a triangle is 180°
the angles are (x-40) , (x-20) and (x/2 - 10).
Sum = (x-40) + (x-20) + (x/2 - 10) = 180
⇒ 5x/2 - 70 = 180
⇒ 5x/2 = 180+70 = 250
⇒ x = 250×2/5
⇒ x = 100
Angles are:
x-40 = 100 - 40 = 60
x - 20 = 100 - 20 = 80
x/2 - 10 = 100/2 - 10 = 40
the angles are (x-40) , (x-20) and (x/2 - 10).
Sum = (x-40) + (x-20) + (x/2 - 10) = 180
⇒ 5x/2 - 70 = 180
⇒ 5x/2 = 180+70 = 250
⇒ x = 250×2/5
⇒ x = 100
Angles are:
x-40 = 100 - 40 = 60
x - 20 = 100 - 20 = 80
x/2 - 10 = 100/2 - 10 = 40
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