Question

The angles of a cyclic quadrilateral abcd are a= 6x +10 b= 5x c=x+y and d=3y-10

Answer 1

Step-by-step explanation:

a+c=180. (angles of a cyclic quad are supp.)

b+d=180. (_do_)

( 6x+10)+(x+y)=180

6x+10+x+y=180

7x+y=180-10

7x+y=70

x+y=10. .....(1)

now, (5x)+(3y-10)

5x+3y-10

5x+3y=10. .......(2)

from eq(1)-

x=10-y

Put value of x in eq (2)

5(10-y)+3y=10

50-5y+3y=10

-2y=10-50

-2y=-40

y=20

Put the value of y in eq(1)

x+20=10

x=10-20

x=-10

Now u can solve for angle a, b ,c and d respectively. BY substituting value of x and y.