The angles of a cyclic quadrilateral ABCD are ∟A = 6x+10°, ∠B= 5x°, ∠c= (x+4) &∠D =3y-10°. Find x &y.
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La+Lb+ Lc +Ld =180
6a+10+5a+a+4+3b-10=180
12a+3b=180-4
12a+3b=176
I hope it's help u....
THANKS
6a+10+5a+a+4+3b-10=180
12a+3b=180-4
12a+3b=176
I hope it's help u....
THANKS
shreyadubey2:
welcome
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