Question

The angles of a cyclic quadrilateral ABCD are angle A =6x +10° angle B=5x° angle c=x+y° angle and angle D =3y-10° find x and y and hence the value of the four angles

Answer 1

Answer:

x=30 and y=0

Step-by-step explanation:

the opposite angles of a cyclic quad is 180 deg

<A+<D=180DEG

6x+10+3y-10=180deg

6x+3y=180deg.... (1)

<B+<C=180deg

5x+x+y=180deg

6x+y=180deg.... (2)

6x+3y=180deg

-6x-y=-180deg

y=0

and x=30

hope this helps

:-)