The angles of a cyclic quadrilateral ABCD in degrees are ∠A=2x, ∠B=(6y+10), ∠C=(2x+y) and ∠D= (x+10). Then measure of ∠C in degrees is
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Step-by-step explanation:
A+C=18o° [ opposite angles of cyclic quad.]
2x+6y=17o°------(1)
Similarly
B+D=18o°
2x+y+x+1o=18o
3x+y=17o----(2)
by elimination method you can find value of x and y and put them in their value
Hope you will get your answer!!!
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