Question

The angles of a hexagon are: x, x + 10°, x + 20°, x + 30°, x + 40° and x + 50 °. Find x. ​

Answer 1

Answer:

∴ Angles of hexagon are x+10∘,2x+20∘,2x−20∘

3x-50,x+40 & x+20

We know sum of angles = 720

x+10+2x+20+2x-20+3x-50+x+40+x+20=720

⇒10x=700

x=70

Hence value of x is 70.

Answer 2

★ Given -:

The angles of hexagon are - x , x+10 , x+20 , x+30 , x+40 and x +50 .

★ To find-:

The value of x .

★ Solution -:

We know that ,

The sum of all interior angles of a polygon =

180(n -2) , where n is the number of sides of the polygon .

Hexagon has 6 sides .

→ n = 6.

180 ( 6 - 2)

= 180 × 4

= 720° .

Sum of all angles of hexagon = 720°

x + (x+10) + (x+20) + (x + 30) + (x +40) + (x+50) = 720

6x + 150 = 720

6x = 720 - 150

6x = 570

$x = \dfrac{\cancel{570}}{\cancel{6}}$

$\bold \purple { x = 95^{\circ}}$