The angles of a hexagon are: x, x + 10°, x + 20°, x + 30°, x + 40° and x + 50 °. Find x.
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Answer:
∴ Angles of hexagon are x+10∘,2x+20∘,2x−20∘
3x-50,x+40 & x+20
We know sum of angles = 720
x+10+2x+20+2x-20+3x-50+x+40+x+20=720
⇒10x=700
x=70
Hence value of x is 70.
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★ Given -:
The angles of hexagon are - x , x+10 , x+20 , x+30 , x+40 and x +50 .
★ To find-:
The value of x .
★ Solution -:
We know that ,
The sum of all interior angles of a polygon =
180(n -2) , where n is the number of sides of the polygon .
Hexagon has 6 sides .
→ n = 6.
180 ( 6 - 2)
= 180 × 4
= 720° .
Sum of all angles of hexagon = 720°
x + (x+10) + (x+20) + (x + 30) + (x +40) + (x+50) = 720
6x + 150 = 720
6x = 720 - 150
6x = 570
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