the angles of a Pentagon are in arithametic sequence prove that it's smallest angle is greater than the 36?
Answers
Answer:
37
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Answer:
Yes , smallest angle is 36
Step-by-step explanation:
The sum of all the angles in a pentagon are 540
Number of angles in a pentagon be 5
Given the angles are in arithmetic progression , the first angle be a, and the common difference be d
Sum of an arithmetic progression of n terms is given by Sum = (2a+(n-1)d)×n÷2
In this case n=5 and the total sum is 540
For ease of simplification I am considering the 5 angles to be a-2d, a-d, a, a+d, a+2d
By data the sum of all the angles of = 540
which gives as 5a=540
a= 108
The smallest angle is a- 2d and I am considering it to be 36
which gives d=36
And now evaluating all the angles with the smallest angle as 36 and finding their sum is equal to exact 540 and anything lesser than that will result in sum less then 540, hence the smallest angle should be greater than or equal to 36