Question

The angles of a Pentagon are in arithmetic sequence .prove that its smallest angle is greater than 36°​

Answer 1

Answer:

Say the angles are a , a + d , a + 2d ,a + 3d , a + 4d degrees, then we have 5a + 10d = 540 or a + 2d = 108. We can thus rewrite the angles as 108−2d , 108−d ,108 ,108+d ,108+2d , and since the pentagon is convex we must have 108+2d≤180 or d≤36. The largest value of d, 36°, will lead to the minimum smallest angle, which is also 36°.

Step-by-step explanation:

hope it helps....! please mark me as brainliest

Answer 2

Answer:

answer for the given problem is given