The angles of a pentagon are in the ratio 3: 5:6: 7:9. Find the measure of each angle.
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The interior angles of a pentagon are in the ratio 4:5:6:7:5.
Let angles are 4x,5x,6x,7x and 5x.
Sum of all angles of a polygon, having n sides = 180
o
(n−2)=180
o
(5−2)=540
o
Now,
4x+5x+6x+7x+5x=540
o
27x=540
o
x=20
o
Angles are
4x=4×20
o
=80
o
5x=5×20
o
=100
o
6x=6×20
o
=120
o
7x=7×20
o
=140
o
5x=5×20
o
=100
o
Hope it helps
Please mark it as brainliest please
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