Question

The angles of a pentagon are x, (x-10),(x+20),(2x-44) and (2x-70) . Calculate x

Answer 1

Sum of interior angles of pentagon=(5-2)×180°
=3×180°=540°.
Now,
x+(x-10)+(x+20)+(2x-44)+(2x-70)=540°
7x-104=540
7x=540+104
x=644÷7
x=92° ans.

Answer 2

Answer:

$x = 92$

Step-by-step explanation:

Sum of interior angles of a polygon having n sides =

$(n - 2)180°$

here,pentagon is given;n=5

The angles of a pentagon are x, (x-10),(x+20),(2x-44) and (2x-70) .

Sum of all interior angles= 540°

$x + x - 10 + x + 20 + 2x - 44 + 2x - 70 = 540 \\ \\ 7x - 104 = 540 \\ \\ 7x = 540 + 104 \\\\ 7x = 644 \\ \\ x = \frac{644}{7} \\ \\ x = 92°$

Hence angles are 92°,82°,112°,140° and 114°

Hope it helps you.