The angles of a pentagon are x°, (x -10)°,(x +20)°, (2x-44)°, and (2x - 70)°.Find its each angle
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sum of angles in a pentagon= 540
x+x-10+x+20+2x-44+2x-70=540
7x= 540+10-20+44+70
7x= 644
x= 92
so,
angles are
x=92
x-10= 92-10= 82
x+20= 92+20= 112
2x-44= 184-44= 140
2x-70= 184-70=114
x+x-10+x+20+2x-44+2x-70=540
7x= 540+10-20+44+70
7x= 644
x= 92
so,
angles are
x=92
x-10= 92-10= 82
x+20= 92+20= 112
2x-44= 184-44= 140
2x-70= 184-70=114
mahesh884177:
thank you very much
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MARK BRAINLIEST
MARK BRAINLIEST
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