The angles of a pentagon are x°,( x+20°) ,(x+40°) ,(x + 60°) and (x+ 80°). find the measure of the angles
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Answered by
4
the sum of angles of a Pentagon is 540
x+20, x+40, x+60, x+80
=5x+20+40+60+80=540
=5x+200=540
=5x=540-200
=5x=340
x=68
=angles are
68, 68+20, 68+40, 68+60, 68+80..
x+20, x+40, x+60, x+80
=5x+20+40+60+80=540
=5x+200=540
=5x=540-200
=5x=340
x=68
=angles are
68, 68+20, 68+40, 68+60, 68+80..
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Answered by
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hey dear ur solution ••••••♀♀♀♀●●●●◆
●●◆●◆
x+x + 20+ x+40+x+60+x+80=540
5x+100+100=540
5x=540-200
5x=340
x=340/5
x=68°
ur Angle are......
1.. x=68°
2•(x+20)=68+20=88°
3•x+40=68+40=108°
4• x+60=68+60=128°
5•x+80=68+80= 148°
>>>>>>>>
>>>
<<<<<<<<
l hope it's help u....
marks. as brainlist answer......
●●◆●◆
x+x + 20+ x+40+x+60+x+80=540
5x+100+100=540
5x=540-200
5x=340
x=340/5
x=68°
ur Angle are......
1.. x=68°
2•(x+20)=68+20=88°
3•x+40=68+40=108°
4• x+60=68+60=128°
5•x+80=68+80= 148°
>>>>>>>>
>>>
<<<<<<<<
l hope it's help u....
marks. as brainlist answer......
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what
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I am marking
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