The angles of a quad. are in A.P , whose common difference is 10 .Find the angles
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let the 4 angles be (a-3d),a-d,a+d,a+3d
sum of all the angles in the quadrilateral=360
so a-3d+a-d+a+d+a+3d=4a=360
a=90
but the angles are a-3d=a-30=90-30=60 as d=10
a-d=90-10=80
a+d=100
a=3d=120
sum of all the angles in the quadrilateral=360
so a-3d+a-d+a+d+a+3d=4a=360
a=90
but the angles are a-3d=a-30=90-30=60 as d=10
a-d=90-10=80
a+d=100
a=3d=120
Anonymous:
your answer is wrong as d = 10 is given.
i also used d=10 see the 4th step from last
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