the angles of a quadliteral are in ap whose common difference is 10°, find the angles
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2
Answer:
75°
85°
95°
105°
Step-by-step explanation:
Let the smallest angle be 'a'
d=10
Since, a quad. has four angles
so, n=4
Since sum of all angles is 360.
So,
n/2{2a+(n-1)d}=360
4/2{2*a+(4-1)10}=360
2{2a+30}=360
4a+60=360
4a=300
a=300/4
a=75
1st angle=75
2nd angle=75+10=85
3rd angle=85+10=95
4th angle=95+10=105
You can check as well
75+85+95+105=360
And, common difference between them is 10.
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