The angles of a quadrilateral ABCD are A=(5x)°,B=5(x+2)°,C=(6x-20)° and D=6(x+3)° then find angle B
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Answer:
B=90 degree
Step-by-step explanation:
sum of angels of quadrilateral=360
=5x +5x+10+6x-20+6x+18=360
=22x+8=360
=22x=360-8
=22x=352
=x=352/22
=x=16 degree
Now angle B=5(x+2)
=5(16+2)=5*18=90(ans)
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