The angles of a quadrilateral ABCD taken in an order are in the ratio 3 : 7 : 6 : 4. Then
ABCD is a
(a) kite (b) parallelogram (c) rhombus (d) trapezium
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D) Since all sides measure different, the answer will be trapezium
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Given : Ratios of angles of quadrilateral are 3:4:6:5
Now,
Let the angles of quadrilateral be 3x, 7x, 6x and 4x.
We know that,
The sum of the angle of a quadrilateral = 360°
3x + 7x + 6x + 4x = 360°
20x = 360°
x = 360°/20
x = 18°
Now,
The angles are,
⇒ ∠A=3x=54°
⇒ ∠B=7x=126°
⇒ ∠C=6x=108°
⇒∠D=4x=72°
⇒∠BCE=∠ADC=72°
Since the corresponding angles are equal, i.e BC∥AD
∴ Sum of interior angles
⇒∠A+∠B=126°+54°=180°
⇒∠C+∠D=108°+72°=180°
∴ ABCD is a trapezium.
Hence, the answer is trapezium.
Look at attachment for diagram
Hope you understand
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