The angles of a quadrilateral are (5x), 5(x+2),
(6x-20) and 6(x + 3)º respectively. Find i) The
value of x ii) each angles of a quadrilateral is
360°.
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Answered by
2
Answer:
ROUNDING OFF THE DIVIDED TO NEAREST 100 IS 600 AND THE DIVISOR TO THE NEAREST 10 WILL BE 20..
Answered by
18
Answer:
Sum of each angle of a quadrilateral is 360
Hence, 5x + 5(x+2) + (6x-20) + 6(x+3) = 360°
5x + 5x + 10 + 6x - 20 + 6x + 18 = 360 °
22x + 8 = 360 °
22x = 360 ° - 8
22x = 352°
x = 16° ... ans i
angle A = 80
angle B = 120
angle C = 76
angle D = 114
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