The angles of a Quadrilateral are in A.P. and the greatest angle is double the least . Find angles of the quadrilateral in radian
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Answer:
Let the angles be (a−3d)
0
,(a−d)
0
,(a+d)
0
,(a+3d)
0
being the common difference of the A.P.
Therefore, sum of all the angles of a quadrilateral is always 360
0
.
(a−3d)
0
+(a−d)
0
+(a+d)
0
+(a+3d)
0
=360
0
4a=360
0
a=90
0
.....(i)
It is given that the greatest angle is twice of the least
Therefore, a+3d=2(a−3d)
⇒a=9d
Substituting the value of a from (i)
90
0
=9d
d=10
0
Hence the least angle is (a−3d)
0
=90
0
−30
0
=60
0
=
3
π
Step-by-step explanation:
hope it will help you
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