Question

the angles of a quadrilateral are in A.P . If the least angles is 15⁰ then find the remaining angles.​

Answer 1

Answer:

sum of the 4 angles of a quadrilateral is 2π

=2×180°=360°

the least angle is 15 °

let the common difference is x

then 2nd angle =(15+x)°

3rd angle (15+2x)°

4th angle(15+3x)°

then,

15+15+x+15+2x+15+3x=360

=> 60+6x=360

=> 6x=360-60

=> 6x=300

=> x=300/6

=> x=50

then the angles are 15°,(15+50)°=65°,(15+2×50)°

=115°,(15+3×50)°=165°

Answer 2

Answer:

nice patilbhagya great idea

I will definitely try it