Question

the angles of a quadrilateral are in A.P whose common difference is 10° .find the angles​

Answer 1

Answer:

let angles be a,a+10,a+20,a+30

now,

since sum of all angles of quad.is 360

therefore 4a+60=360

a=75now substitute values

Answer 2

Explanation:

quadrilateral has 4 sides so

sum of angle is (n-2)×180

=360

cd =10

sum of 4 term= n/2(2a+(n-1)d);

360= 2×(2a+3×10);

180=2a+30;

150 = 2a

a= 75

so 4 angles are,75,(75+10),(85+10),(95+10)

i.e, 75,85,95,105

hope you are satisfied

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