The angles of a quadrilateral are in ap d=10 find those angles
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please refer to the attachment above
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please refer to the attachment above
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Let the angles of the quadrilateral be
(a-3d),(a-d),(a+d),(a+3d)
As we know that sum of angles of quadrilateral is 360°
so
a-d+a-d+a+d+a+2d=360°
4a=360°
a=90°
So the angles are
80°, 60°, 100°, 120°
(a-3d),(a-d),(a+d),(a+3d)
As we know that sum of angles of quadrilateral is 360°
so
a-d+a-d+a+d+a+2d=360°
4a=360°
a=90°
So the angles are
80°, 60°, 100°, 120°
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