Question

The angles of a quadrilateral are in AP,if the smallest angle is 15 degree Find the other angles.​

Answer 1

So, here

a (1st term of AP)=15

Let 'd' be the common difference.

n = 4

AP: 15, 15+d, 15+2d, 15+3d

We know that sum of all the angles of a quadrilateral is 360°.

15+ (15 + d)+ (15 + 2d)+ (15 + 3d)=360°

60 + 6d = 360

6d = 360-60

6d = 300

d = 300/6 = 50

Hence,

Angle 1 = 15°

Angle 2 = 15+d = 15+50 = 65°

Angle 3 = 15+2d = 15+2(50) = 15+100 = 115°

Angle 4 = 15+3d = 15+3(50) = 15+150 = 165°

Hope it helps!!! :)

Answer 2

Answer:

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