Question

The angles of a quadrilateral are in AP. The greatest angle is double the least. Find all the four angle.

Answer 1

the angles of quadrilateral are
(a-3d)+(a-d) +(a+d)+(a+3d)=360°----(sum of quadrilateral's
all angles)
a+a+a+a+3d+d-d-3d=360°
4a+4d-4d=360°
4a=360°
a=90°

Let, a+3d is greater than a-3d
a+3d=2(a-3d)
a+3d=2a-6d
3d+6d=2a-a
9d=a
but a=90
d=90/9
d=10

a-3d=90-3×10=90-30=60°

a-d=90-10=80°

a+d=90+10=100°

a+3d=90+3×10=90+30=120°

the angles of quadrilateral are 60°, 80°, 100°, 120° respectively in an app whose greatest angle is double of least

I hope this will help you

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