THE ANGLES OF A QUADRILATERAL ARE IN AP WHOSE COMMON DIFFERENCE IS 48 FIND THE ANGLES
Answers
Answered by
3
let first angle be x and(a)
second angle =x+48( a+d)
third angle = x+2*48( a+2d)= x+96
fourth angle =x+3*48( a+3d)= x+144
sum of angles in quadrilateral =360
so add all angles
x+x+48+x+96+x+144=360
4x+288=360
4x=72
x=18
x+48=66
x+2*48=114
x+3*48=162
second angle =x+48( a+d)
third angle = x+2*48( a+2d)= x+96
fourth angle =x+3*48( a+3d)= x+144
sum of angles in quadrilateral =360
so add all angles
x+x+48+x+96+x+144=360
4x+288=360
4x=72
x=18
x+48=66
x+2*48=114
x+3*48=162
Priya999:
plsss mark branliest
if u have any doubts u can ask me
I HAVE SO MANY DOUBT SEE THE QUESTIONS I AM ASKED TO BRAINLY AND PLEASE ANSWER IT FAST
HELLO
PLEASE SEND ME THE ANSWERS OF OTHER QUESTIONS
Similar questions