Question

the angles of a quadrilateral are in AP whose common difference is 10 degree find the angles

​

Answer 1

Answer:

Angles in AP are a+3d, a+d, a-d, a-3d with common difference 2d

A/to question. 2d=10, d=5

Now, sum of angles in a quadrilateral is 360°

So a+3d+a+d+a-d+a-3d=360°

4a=360°

a=90°

Now angels are

a+3d=90°+3(5)=90°+15=105°

a+d=90°+5=95°

a-d=90°-5=85°

a-3d=90°-15=75°

Hope this help you :-) :-) :-)

Answer 2

Answer:

Pls mark as brainliest

Step-by-step explanation:

 let the angles of the quadrilateral be   X , X+10 . X+20 ,X+30

 the sum of the angles of the quadrilateral = 360 degrees

  X+ X+ 10 + X+20 +X +30  = 360

====> 4X +60  = 360

==>4X = 360 - 60 = 300

====> X = 75

 The angles of the quadrilateral are  75,  85,  95,  105 degrees