Question

the angles of a quadrilateral are in AP with d = 10, find the angles.​

Answer 1

Answer:

given= 10°

let us take angles as a-d , a , a+d , a+2d

now we know that sum of all quadrilateral is 360°

so we get

a-d + a + a+d + a+2d= 360°

4a+ 2(10) = 360°

a= 85°

first angle = a-d = 85 - 10= 75°

second angle a= 85°, third angle = a+2d= 85+ 2(10)= 85+20= 105°

fourth angle = a+d = 85+ 10= 95°

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

let be the angle a-3d,a+d,a-d,a+3d....

sum of angle=360

4a=360

a=90

angles are 60,100,80,120