Question

The angles of a quadrilateral are in arithmetic progression and the greatest angle is twice the least angle. What is the greater angle in radians?

Answer 1

Answer:

Let the angles be a−d,a,a+d, where a and d are first term and common difference respectively.

∴a−d+a+a+d=180                       (∵sum of angles of trianlge)

3a=180⇒a=60

Also, a+d=2(a−d)                                   (Given)

⇒60+d=2(60−d)

⇒3d=60⇒d=20

Therefore, angles are 60−20,60,60+20 i.e.40,60,80

Difference =80−40=40

Step-by-step explanation: