Math, asked by virkgoldygoldy, 8 months ago

The angles of a quadrilateral are in the ratio
of 4x", (5x+20)". (6x + 8)" and (7x+2)". Find
all the angles of quadrilateral.​

Answers

Answered by annavarapusrinivas3
4

Answer:

the answer will be 60,95,98,107

Step-by-step explanation:

we all know that sum of interior angles of quadrilateral is 360 degrees .

now the given equation is:

4x,(5x+20),(6x+8),(7x+2) .

so what we gave to do is equal the given equation with 360.

we get, 4x+5x+20+6x+8+7x+2=360

22 X + 30 =360

22 X=360-30

=330

X=330/22

(X=15)

so , 4x= 4×15 =60

5x+20=75+20=95

6x+8=90+8=98

7x+2=105+2=107 .

so ,add these angles 60+95+98+107 =360

so ,the required angles for quadrilateral are 60,95,98,107.

Hope it will help you...

Thank me and mark me as brainliyest...

Answered by vedanshaggarwal2006
0

Answer:

HEY MATE!!! HOPE THIS HELPS YOU.

Step-by-step explanation:

∠A + ∠B + ∠C + ∠D = 360° (Sum of all angles of a quadrilateral is 360°)

(4x)° + (7x+2)° + (6x+8)° + (5x+20)° = 360°

22x + 30° = 360°

22x = 360° - 30°

22x = 330°

x = \frac{330}{22} = 15°

∠1st = 4 × 15° = 60°

∠2nd = 7 × 15° + 2 = 107°

∠3rd = 6 × 15° + 8 = 98°

∠4th = 5 × 15 + 20 = 95°

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