Question

The angles of a quadrilateral are (x). (x - 10), (x + 30) and (2x), find the smallest
angle​

Answer 1

Answer:

smallest angle be 68 degree

Answer 2

$\huge{\underline{\underline{\bf{\purple{answer}}}}}$

$\angle a + \angle b + \angle c + \angle d = 360 \\ \\ x + x - 10 + x + 30 + 2x = 360 \\ \\ 5x = 360 - 30 \\ \\ 5x = 330 \\ \\ x = \frac{330}{5} = 66$

x = 66°

x - 10 = 66 - 10 = 56°

x + 30 = 66 + 30 = 96°

2x = 2 × 66 = 132°

SMALLEST ANGLE IS ( X - 10 ) i.e 56°

☆BE BRAINLY☆