Question

The angles of a quadrilateral are x° ,(2x+13 )°,(3x+10)° , (x-6)°.Find the value of x°.

Answer 1

Sum of angles in a quadrilateral =360

So x° +(2x+13)°+(3x+10)°+(x-6)°=360

7x + 13+10-6= 360

7x+ 17 = 360

7x =360-17

7x= 343

x = 343/7

x = 49