the angles of a quadrilateral are x0, (x + 20° ), (x − 50° ) and 2x° . find the greatest angle.
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x° + (x + 20)° + (x - 50)° + 2x°= 360°.......( Angles of a quadrilateral)
x + x + 20 + x - 50 + 2x = 360°
5x - 30= 360
5x= 360 + 90
5x= 390
x= 390/ 5
x= 78
The angles of the quadrilateral:
1. x° = 78°
2. (x + 20)° = 78+ 20= 98°
3. (x - 50) = 78- 50= 28°
4. 2x°= 2 × 78= 156°
Therefore, the greatest angle of the quadrilateral will be 156°
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