Math, asked by Anonymous, 10 months ago

The angles of a quadrilateral in an Arithmetic Progression. If the least angle is
15degree , then find the remaining angles

Answers

Answered by dishagupta14
4

Answer:

You can see the answer in adjoining pic.

Hope it helps...

Attachments:
Answered by sidggoenka
4

Step-by-step explanation:

Let( a)°, (a+d)°,(a+2d)° and (a+3d)° are the

internal angles of a quadrilateral ABCD which are in A.P. and a=15°(given).

a+a+d+a+2d+a+3d=360°

4a+6d = 360° , put a=15°

4*15+6d° = 360°

6d = 360°-60°=300

d = 50

1st angle = a = 15

2nd angle=a+d=65

3rd angle=a+2d=115

4th angle=a+3d=165

15° , 65° , 115° , 165 . Answer.

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