The angles of a quadrilateral in an Arithmetic Progression. If the least angle is
15degree , then find the remaining angles
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Answer:
You can see the answer in adjoining pic.
Hope it helps...
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Step-by-step explanation:
Let( a)°, (a+d)°,(a+2d)° and (a+3d)° are the
internal angles of a quadrilateral ABCD which are in A.P. and a=15°(given).
a+a+d+a+2d+a+3d=360°
4a+6d = 360° , put a=15°
4*15+6d° = 360°
6d = 360°-60°=300
d = 50
1st angle = a = 15
2nd angle=a+d=65
3rd angle=a+2d=115
4th angle=a+3d=165
15° , 65° , 115° , 165 . Answer.
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