the angles of a quadrilateral in the ratio 1:2:3:4 .find the smallest and the largest angle
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Answered by
200
Let the angles of quadrilateral be
x, 2x, 3x , 4x
sum of all angles of quadrilateral = 360°
x + 2x + 3x + 4x = 360°
10x = 360°
x = 360/10 = 36°
Ans. the four angles are :-
x = 36°
2x = 2 × 36 = 72°
3x = 3 × 36 = 108°
4x = 4 × 36 = 144°
x, 2x, 3x , 4x
sum of all angles of quadrilateral = 360°
x + 2x + 3x + 4x = 360°
10x = 360°
x = 360/10 = 36°
Ans. the four angles are :-
x = 36°
2x = 2 × 36 = 72°
3x = 3 × 36 = 108°
4x = 4 × 36 = 144°
Answered by
177
let angles of queadrilateral be X, 2x, 3x, 4x
X + 2x + 3x + 4x = 360° (sum of all angles of quadrilateral)
10x = 360°
X = 360°/10
X = 36°(smallest angle)
hence, 4x = 4 X 36 = 144° (largest angle)
2x = 2 X 36 = 72°
3x = 3 X 36 = 108°
HOPE IT'S HELP YOU
SHANAYA ⭐
X + 2x + 3x + 4x = 360° (sum of all angles of quadrilateral)
10x = 360°
X = 360°/10
X = 36°(smallest angle)
hence, 4x = 4 X 36 = 144° (largest angle)
2x = 2 X 36 = 72°
3x = 3 X 36 = 108°
HOPE IT'S HELP YOU
SHANAYA ⭐
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