Question

the angles of a quardilateral x°, (x+10)°, (x + 52)°
and 3x°, find the greatest angle?​

Answer 1

Answer:

Since the sum of the angles of a quadrilateral is 360

0

Therefore, x+(3x−40)+2x+(4x+20)=360

0

⇒10x−20=360

0

⇒10x=360+20=380

⇒x=

10

380

=38

Now, x=38⇒2x=2×38=76

3x−40=3×38−40=74

and 4x+20=4×38+20=172

Thus, the measures of the angles are 38

0

,74

0

,76

0

and 172

0