the angles of a quardiletral are in the ratio 3:5:2:8, find the smallest angles give it fast my exam is there
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Sum of all the angles in a quadrilateral = 360°
Let the angles be 3x , 5x , 2x , 8x
∴ 3x + 5x + 2x + 8x = 360°
⇒ 18x = 360°
⇒ x = 360/18
⇒ x = 20°
Therefore, the angles of the quadrilateral are =
3x = 3×20 = 60°
5x = 5×20 = 100°
2x = 2×20 = 40°
8x = 8×20 = 160°
So, the smallest angles is 40°
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